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rustypigeon

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What would you say the correct answer is for this question. I got the correct answer, but I think the question is flawed. Let me know what you think the correct answer is. Then I will tell you what the book says it is, and what I think it should be.

G30SF/F-250

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D???

The 8 inch radius doesn't matter if the handle is connected to the center of the shaft right?

inthefrey

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b. 250

2" is 1/4 dia. of 8"

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Question is flawed. The weight is shown to be in the 2" knob. Weight seems to be outside the 8" radius, too.

Confusing illustration.

Sorry, I saw it backwards. :embarassed:

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Weight is centered and circular, so one should define "raised".

Brian Lee

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I'd have chosen A, but would still not be surprised if the teacher said B was correct, even though it couldn't be, according to the looks of the drawing.

USDMike

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Making the assumption that the handle is approximately double the radius of the 8" disk. The answer is around 125lb or (a), averaged over one rotation.

That's how I would do it anyway.

JRS

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This was my take on it too.

JRS

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D???

The 8 inch radius doesn't matter if the handle is connected to the center of the shaft right?
Nope. Give me a lever long enough, and I can lift the world.

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c....

JRS

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And if you really want to split hairs (aka be a ******), then you also need to add the rotational mass of the assembly (the 2 disks, the shaft, and the handle/lever) to the answer. So none of them are right lol.

bowbender7

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That 2" on the weight side negates 2" of the crank side...

paulbow

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I'd have chosen A, but would still not be surprised if the teacher said B was correct, even though it couldn't be, according to the looks of the drawing.
"ILLUSTRATION DRAWN NOT TO SCALE"

:supergrin:

rustypigeon

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The book says that "B" is correct. Those of you who think "A" is the correct answer are technically correct, at least according to my interpretation of the drawing.

If the handle was positioned on the 8" radius, then B would be the answer. Since the handle is roughly twice the distance of the 8" radius, or 16", you can figure that A is closest to the correct answer.

Its questions like these that you have to wonder if you are supposed to answer the technically correct answer, or the answer you think they want.

I just wanted to make sure that I was not the only one seeing a flaw in the question. Thanks guys.

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Hell, it took me this long to realize that the "1000#" was meant to show a weight attached to the little wheel.

Looked like a drawing note pointing to a wheel that weighed half a ton.

UtahIrishman

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It's a ratio of 2 to 8 ...so 250 lbs

the pic was a bit off but not much.

RenoF250

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The book says that "B" is correct. Those of you who think "A" is the correct answer are technically correct, at least according to my interpretation of the drawing.

If the handle was positioned on the 8" radius, then B would be the answer. Since the handle is roughly twice the distance of the 8" radius, or 16", you can figure that A is closest to the correct answer.

Its questions like these that you have to wonder if you are supposed to answer the technically correct answer, or the answer you think they want.

I just wanted to make sure that I was not the only one seeing a flaw in the question. Thanks guys.
If it was an actual test I would right that on the paper that way you are covered either way.

rustypigeon

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It's a ratio of 2 to 8 ...so 250 lbs

the pic was a bit off but not much.
But the handle is not at 8" and that is the flaw. The handle is roughly twice the 8" radius.

Rick C

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B# (B sharp)......

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