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Dinky has a question!

Discussion in 'OX & Alex Forum' started by Dinky, Mar 17, 2012.

1. DinkyNumpty

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The Earth turns counter-clockwise to the East.

Does it take less energy to drive East, as you are going with the rotation and does it take more energy to drive West, against the rotation?

Or does it take more energy driving East, as you have to drive faster than the earth is rotating to move from one spot to the other or does it take less energy driving West as the Earth is rotating away from the direction you are going??

Dinky would like the too know.....

2. tousGET A ROPE!

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Do you assume a tailwind?

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If you find yourself going the wrong way, a few 10MM's will cancel out the difference, depending on said rotation.

4. DinkyNumpty

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Only if you are behind me and talking

5. uhlawpupGentle Soul

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Congratulations on an intelligent question!

Ignoring atmospheric resistance, it takes the same amount of energy to overcome your vehicle's inertia, since the gravitational center is for all practical purposes right below you, no matter which way on the surface you head.

6. DinkyNumpty

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So if I took a 10mm and shot it to the West, the Earth would speed up and if I shot it to the East once, the Earth would slow and if I shot it twice would the Earth stop?

How is that for an intelligent question?

Last edited: Mar 17, 2012
7. tousGET A ROPE!

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uhlawpup has a portion of the answer. If the Earth were a sphere, the force required to overcome gravity on the surface of the sphere produced by both mass and rotational velocity would be the same.

You mention moving either along the vector of rotation or 180 degrees from the vector of rotation, so your working theory is that movong the in direction or rotation gives you a sort of tailwind and hus, you need less energy, no?

Here's a clue. The two moving objects, car and planet are always moving relative to each other, not idependently.

Let's use a smaller-scale example. Consider, you are on an aircraft traveling 965 kph. Assume that direction of travel, altitude and friction don't affect the experiment. The test procedure is to walk a fixed distance at the constant velocity from the aft forward and walk the same distance, same constant velocity from forward to aft. If your theory is valid, it should take less effort to move aft to forward that forward to aft, no?

Consider, you are moving at 965 kph in some direction. When you walk from the rwar of the aircraft to the front, in the direction of travel, let's say at 2 kph, are you going 2 kph or 967 kph? When you move in the opposite direction, are you moving 2 kph or 963 kph?

Hus! You now have enough information to anwser the question.

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9. tousGET A ROPE!

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Uh, not yes.

Both objects are moving relative to each other. Whichever way you go on the aircraft, you are moving 2 kph and the energy needed is the same, just as it would be if the aircraft were sitting on the ground.

Consider the same aircraft. If you jump up in the air, does the plane move out from under you at 965 kph and smash you into the bulkhead?

Note that if you are standing at the North or South Pole, you can walk around the world in about ten steps.

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11. scratchy wilsonSilver Member

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This thread needs a lava lamp.

12. HandyMan HughNRA Life Member

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And a little Cowbell too.

13. tousGET A ROPE!

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It wasn't Dinky's fault this time.

14. engineer151515

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For Goodness sake, DO NOT throw a treadmill into this analysis.

15. DinkyNumpty

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Most of the time it is my fault butt not this time....

16. DinkyNumpty

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OK, standing on a treadmill with a 10mm

17. tousGET A ROPE!

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Is the treadmill on the rotational axis of the earth?
Is the 10mm cartidge a Buffalo Bore product or a wimpy range round?
Is the Moon in the seventh house?
Jupiter aligned with Mars?

18. vkscottRetired USAF

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You used ass and tail in the same sentence.

19. tousGET A ROPE!

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It is my great talent.

I can do little else.

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