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Penetrate what?Imagine we have two hardcast bullets of the same profile, same diameter, differing only in weight and length. They are both launched so that they have identical momentum(e.g 155gr @1350fps and 180gr @1162fps). Which will penetrate further and why?
Both fired into identical medium. Lets say ballistic gelatin.Penetrate what?
That is the unknown in your example.
For the gold star 💥 as the only response directly answering the question!Its called sectional density. In your example the 155 has a SD of 89, the 180 104. The lighter bullet going faster also slows faster in any medium. If you drove the lighter bullet even faster as a solid, it might match the heavier bullet By increasing momentum, but you have to push it quite a bit higher.
But the lighter bullet in the OP's scenario IS being driven faster, hence why the momentums are the same. But as we both explained, the extra resistance from the higher velocity means the heavier bullet penetrates more. It really is more about that than about the SDs since momentums are the same.Its called sectional density. In your example the 155 has a SD of 89, the 180 104. The lighter bullet going faster also slows faster in any medium. If you drove the lighter bullet even faster as a solid, it might match the heavier bullet By increasing momentum, but you have to push it quite a bit higher.
Where is the gell test to support the posited theoretical conclusions or to raise other issues?Both fired into identical medium. Lets say ballistic gelatin.
But momentum is not based only on velocity.From a math perspective I think a more interesting question is: how much more momentum (velocity) would the lighter bullet need in order to overcome the added resistance due to its higher velocity?
Why i said you would have to increase momentum with higher vel. SD is just another metric showing the ability of a bullet to penetrate.But the lighter bullet in the OP's scenario IS being driven faster, hence why the momentums are the same. But as we both explained, the extra resistance from the higher velocity means the heavier bullet penetrates more. It really is more about that than about the SDs since momentums are the same.
From a math perspective I think a more interesting question is: how much more momentum (velocity) would the lighter bullet need in order to overcome the added resistance due to its higher velocity?
So here is an example. The 165 has higher vel thus momentum, 181 v 167. Expansion is almost identical but the 180 is still higher SD. The diff on penetration is the addl momentum by raising vel.Where is the gell test to support the posited theoretical conclusions or to raise other issues?
| 22.4" |
![]() | .49" | 1101 |
Hornady 180 gr XTP Custom |
| 20.9" |
![]() | .50" | 933 |
1) How are you calculating this? I have not worked with sectional density much but I understand it is weight/diameter squared. For a 40 cal I get (155/7000)/.16 and (180/7000)/.16 or 138 and 160 ?Its called sectional density. In your example the 155 has a SD of 89, the 180 104.
Yes, and yes. It's simply comparative, not real world. It really is only defined at an impact velocity. Most LE trained "firearms experts" opposite of me use muzzle velocity. If my client is so inclined, pretty easy to get them excluded under Daubert for common and simple mistakes.2) Is this calculation always done with the beginning diameter? Doesn't this neglect the bigger final mushroomed diameter (if any) and the lessened penetration it would give?
There is actually a program i use. SD changes as the bullet expands, weight/dia sq, the expanding bullet dia is getting larger, weight is the same. Why its really a metric for solids, not expanding bullets, but its still relative. Drive identical weight bullets the same vel, the larger expanding bullet penetrates less.1) How are you calculating this? I have not worked with sectional density much but I understand it is weight/diameter squared. For a 40 cal I get (155/7000)/.16 and (180/7000)/.16 or 138 and 160 ?
2) Is this calculation always done with the beginning diameter? Doesn't this neglect the bigger final mushroomed diameter (if any) and the lessened penetration it would give?
Thanks.
But in the above example, no.The longer bullet goes deeper... Hmm, there are so many sex jokes to choose from.![]()